If a tree falls in a forest, and nobody is there to hear it, does it make a sound? The answer was obvious to my 12-year-old self — of course it made a sound. More specifically, something ranging from a thud to a thump. There doesn’t need to be an animal present for the tree to jiggle air molecules. Classical physics for the win! Around the same time I was exposed to this thought experiment, I read Michael Crichton’s *Timeline. *The premise is simple, but not necessarily feasible: archeologists use ‘quantum technology’ (many-worlds interpretation and quantum teleportation) to travel to the Dordogne region of France in the mid 1300s. Blood, guts, action, drama, and plot twists ensue. I haven’t returned to this book since I was thirteen, so I’m guaranteed to have the plot wrong, but for better or worse, I credit this book with planting the seeds of a misconception about what ‘quantum teleportation’ actually entails. This is the first of a multi-part post which will introduce readers to the one-and-only way we know of how teleportation works.

Before getting there, given that this is my first post, I should introduce myself: my name is Shaun Maguire and I’m a 2nd year graduate student in the quantum information group at Caltech. I agree with some of the earlier sentiments that it’ll be interesting to see where this blog goes — especially considering that they gave the keys to hooligans like myself. I’m new to this field and certain to get details wrong, but I’ll try to make up for this by providing boundless enthusiasm and a fresh perspective.

Anyways, back to quantum teleportation. To me, the word teleportation is synonymous with *faster than light* transport. So that begs the question, where is the ‘faster than light’ in quantum teleportation? The meta/quantum answer is that it’s both there and it’s not. It’s there in that we can effect instantaneous change over arbitrarily large spatial distances. It’s not there in that we need to transmit classical information between these two locations, abiding by the rules of special relativity, before we can take advantage of the teleported information. Let me explain the process in more detail, trying to do so using both words and notation in parallel.

**The quantum coin: **The story of quantum teleportation starts with two foundational elements of quantum information: *qubits* and *entanglement*. In what follows, I will attempt to explain these two concepts at a level targeting bright aspiring quantum physicists (experts know these topics way better than myself and people in between have resources like Nielsen and Chuang and John Preskill’s notes.)

For now, qubits (short for *quantum bits*) are to quantum information what bits are to classical information (the language in which computers operate). There are many different implementations for a classical bit (the familiar “0” and “1”). It can be represented by any system which has two states. It is convenient (for later use) to introduce notation which represents such a state abstractly as $latex left|0right>$ and $latex left|1right>.$ Examples include: current in a circuit above/below a threshold (classical computer), right/left circular polarization of photons (optical computer) and sequences of base pairs in DNA (molecular computer). Caltech has been a pioneer in all three of these forms of computing, with seminal contributions from the research groups of: Carver Mead, Amnon Yariv and Erik Winfree (this list is far from comprehensive regarding the contributions coming from Caltech). I would like to think that IQIM is making contributions of a similar scale to quantum computing, but obviously only time will tell.

A classical bit is always in a definite state — for example it is either: on/off, left/right or A/T/C/G (not quite a bit, but close enough) — where for our purposes this physical underpinning is abstracted away and represented by 0s and 1s. A qubit is a different beast entirely. It exists in a superposition $latex left|psiright> =alphaleft|0right> + betaleft|1right>$, where $latex alpha$ and $latex beta$ are complex numbers such that $latex |alpha|^2 + |beta|^2=1$, and $latex |alpha|^2$ is the probability that a measurement of this qubit would yield $latex left|0right>$ (while $latex |beta|^2 = 1 – |alpha|^2$ is the probability of getting the state $latex left|1right>$ after the measurement). This is easy to say, but what does it mean? You can think of a superposition as a ‘mixture’ of the two states. It’s neither one nor the other, it’s a ‘mixture’ of the two. However, when a scientist *measures* the qubit, it *collapses* to a definite state. It becomes either a zero or a one. In technical language, the outcomes of measurements are eigenfunctions, even though the state before the measurement can be a linear combination of different eigenfunctions. The subtlety of this business is evidenced by the great number of books that have been written on the topics of Schrödinger’s cat and different interpretations of quantum mechanics. Much of this literature stems from confusion about what’s going on in the time between preparing a quantum state and measuring it.

It’s my personal opinion that for the time being, you’d be best served by sweeping these subtleties under the rug and taking it on faith that qubits are both *probabilistic* and don’t have a *defined state* until they are measured. I promise that your intuition improves as you work with quantum systems (but the difficulty in explaining these subtleties to the non-initiated remains!) The first condition, that qubits are *probabilistic*, means that even if there was a machine which prepared millions of identical qubits, and stored them in little boxes (wrapped like Holiday presents?), then when you measured different qubits, you wouldn’t necessarily obtain the same result! The probability of measuring the state corresponding to $latex left| 0 right>$ would be $latex |alpha|^2$ and the probability of getting $latex left| 1 right>$ would be $latex |beta|^2$. You might be thinking that this is perfectly acceptable, maybe the machine flipped a coin and chose a state accordingly, before preparing the boxes? The probabilistic aspect of qubits has a classical analog in the flipped coin. But it’s the second property of qubits, when you try to understand what happens in the time between preparing a quantum state and measuring it, where your intuition really begins to deviate from classical physics. The important thing is that the qubit hadn’t ‘made up its mind’ before the measurement. We can perform experiments which conclusively show that the qubit wasn’t in a definite state before the measurement — it wasn’t yet a 0 or a 1.

To make the differences between bits and qubits more concrete, I’ll introduce a silly conception of a two-state system which is near and dear to my heart — I run frequently and I therefore eat lots of dessert, so my mind thinks in terms of cookies and brownies. Using this model, bits are EITHER cookies OR brownies. Qubits are superpositions of cookies and brownies. For example, a qubit could be in an unequal superposition : $latex sqrt{frac{1}{4}}left|text{cookie}right> +sqrt{frac{3}{4}}left|text{brownie}right>$. Let’s imagine there are classical and quantum factories which produce bits and qubits respectively. To say that the classical factory is *probabilistic* might mean that there’s a long assembly line which can produce both cookies and brownies. Let’s say that when you show up at the factory to buy a dozen cookies you have the option of ordering the house specialty — ‘the probabilistic dozen.’ What this means is that every time someone orders another ‘probabilistic dozen,’ an attendant flips an unfair coin (1/4 heads, 3/4 tails) twelve times and packs the box accordingly. Without looking in the box, you take it home to serve to your family after dinner (or to selfishly devour the whole box after a long run.) This particular box may have three cookies, it may have four, or any other number between zero and twelve. You don’t know before you open the box — however, the number of cookies in the box is very well defined — the attendant who packed the box knows exactly how many cookies vs brownies are in there, even though you don’t know.

The quantum factory is very different. In this case, there are two ways that the factory could prepare something akin to a ‘probabilistic dozen.’ First, the attendant could do exactly the same thing as before, flipping a coin and then putting either cookies or brownies in the box accordingly. A cookie would have the state $latex sqrt{1}left|text{cookie}right> +sqrt{0}left|text{brownie}right>$, and a brownie the state $latex sqrt{0}left|text{cookie}right> +sqrt{1}left|text{brownie}right>$. When you open the box, you’ll have a certain number of cookies and a certain number of brownies and the attendant will know exactly how many you will obtain*. Moreover, the cookies and brownies were prepared differently. The second, fundamentally different way to serve up a ‘probabilistic dozen’ would be to package twelve identical quantum brown-kies in the superposition: $latex sqrt{frac{1}{4}}left|text{cookie}right> +sqrt{frac{3}{4}}left|text{brownie}right>$. Again, the attendant knows exactly what they packed for you — twelve identical quantum brown-kies — but they don’t know how many cookies and brownies you’ll obtain when you open your box. When you open the box for the first time, each quantum brown-kie is forced to collapse into a definite cookie or brownie state. It will then take this form forever after, unless some additional quantum magic is performed. Also, it’s worth noting that the quantum brown-kies don’t have to ‘make up their mind’ every time you open the box. Only the first time — the first measurement.

In summary, a qubit is a superposition of two states: $latex left|psiright> =alphaleft|0right> + betaleft|1right>$. It’s not exclusively in either state, it’s still in limbo, with a proclivity towards each of its two possible states governed by $latex |alpha|^2$ and $latex |beta|^2$. It chooses between the two when it’s measured for the first time. This would be a very natural segue into quantum computation, but I’m going to stick with quantum teleportation for now. That means I also need to explain entanglement.

My next post will attempt to do just that: explain entanglement. Why should you read it? Because at the end of this series, you’ll be able to understand how we built a quantum teleportation machine at Caltech.

Grant TeplyAugust 13, 2012 at 2:21 pmHi Shaun. Were you perhaps inspired by the mystery of the quantum cakes? The article should be accessible to the undergraduate.

http://research.physics.illinois.edu/QI/Photonics/papers/QuantumCakes.pdf

shaunmaguireAugust 13, 2012 at 7:52 pmI wasn’t aware of their article, but I think they must also be runners!

ShermanAugust 13, 2012 at 6:03 pmThe states of hunger/satiation for me have collapsed into a certainty: hunger. Damn!

David AcevedoAugust 13, 2012 at 8:24 pmThank you. Now I will think of qubits whenever I eat cookies or brownies! Seriously though, thanks. This was a nice post. I look forward to the next part.

Jason DickAugust 13, 2012 at 8:31 pmWhile this post is largely correct, I think it’s focusing too much on measurement. It is entirely possible to collapse a quantum state without measuring it, as seen in this experiment, for example:

http://prl.aps.org/abstract/PRL/v77/i24/p4887_1

My rather naive understanding is that a large part of the difficulty with quantum computation lies in avoiding the collapse of the wavefunction, which means a whole lot more than simply not measuring it. It means ensuring that the quantum states (the qubits) remain isolated from their surroundings for long enough to perform the computation.

Granted, quantum computing wasn’t my field, so there may be other difficulties that are more significant that I am unaware of. But either way, preventing collapse of the wavefunction requires more than just not measuring the system.

hixgridAugust 14, 2012 at 4:57 pmQuantum Teleportation WILL definetly be possible in the next future. What I am wondering is how to define the write process in QED computing. A ternary logic is implemented (-1/0/1), how can we use the zero to do this? A quantum hall induced microcosm is applicable. The decoherence problem will be solvable. Finally I think that QED-computing and space are on ‘the same plane’ means that QED vacuum may include (error correction) computer code. The data redundancy of the universe is induced by recursive symmetries (in the spin states) and there are also dynamic asymmetries induced (also) by topology of space (no annihilation process due to this). Hence I assume that research in Antimatter (QED) computing will be the next step. QuBits and Black Holes are also a compelling challenge – Black Holes may be vortices of plasma, EM-fields and the electric universe theory are unravelling more things. Photonics is embedded in these therories. Think also about Kernel Method and Hilbert Space reversable computing. Still more to come, looking forward to your next post!

Around the web | kryptomusingAugust 14, 2012 at 9:28 pm[…] People from the Institute for Quantum Information and Mattter @ Caltech, now have a blog : Quantum Frontiers. The blog already has some excellent articles like ‘How to build a teleportation machine: Intro to qubits‘ […]

Sankalp GhatpandeAugust 14, 2012 at 9:44 pmNice post! Glad that IQIM now has a lively blog. Looking forward for learning more from you lot.

And Grant Teply loved the Quantum Cakes:)

Sankalp GhatpandeAugust 14, 2012 at 9:57 pmAnd the google reader has new article ‘The Eiger et al.’ but unable to find it. Was it deleted?

-Teleportation and The Tenth Dimension | David Reneke | Space and Astronomy NewsAugust 16, 2012 at 5:23 pm[…] How to build a teleportation machine: Intro to qubits (quantumfrontiers.com) var fbShare = {url: 'http://www.davidreneke.com/teleportation-and-the-tenth-dimension/',size: 'large',} Sharing is caring. […]

Weekly links for August 19 « God plays diceAugust 19, 2012 at 5:01 pm[…] How to build a teleportation machine: intro to qubits. (On a related note I’ve been enjoying Umesh Vazirani’s Coursera course Quantum mechanics and quantum computation. […]

How to build a teleportation machine: Intro to entanglement | Quantum FrontiersAugust 19, 2012 at 9:14 pm[…] going to reward myself after writing this post by devouring a pint of “half-baked” brown-kie ice cream (you can’t find this stuff in your local […]

How to build a teleportation machine: Teleportation protocol | Quantum FrontiersSeptember 17, 2012 at 11:25 am[…] last two posts introduced quantum bits (qubits) and entanglement. Qubits (superpositions of 0s and 1s) are the fundamental units in quantum […]

LaurindaJune 7, 2014 at 8:34 pmThe trinocular microscopes are very expensive and are required for

microphotography. As around 40 Mbps of data can be put up by each

channel, the four downstream channels can supply a maximum of 160 Mbps of throughput.

92 standard modem, you have the best and latest modem and you should be able to get faster speeds.

uffca.caJuly 5, 2016 at 11:36 amAn important thing to notice is that our giant fax machine is not intended to transfer matter and energy, just like a regular fax machine would not be used to transmit blank papers. So can we build a classical teleportation device as described?